Question

将多项式(3a-4b)(7a-8b)-(11a-12b)(8b-7a)分解因式,正确的结果是

Answer 1

(3a-4b)(7a-8b)-(11a-12b)(8b-7a)
=(3a-4b)(7a-8b)+(11a-12b)(7a-8b)
=(7a-8b)[(3a-4b)+(11a-12b)]
=(7a-8b)(14a-16b)
=2(7a-8b)²

Answer 2

解：原式=(3a-4b)(7a-8b)+(11a-12b)(7a-8b)
=(7a-8b)(3a-4b+11a-12b)
=(7a-8b)(14a-16b)
=2(7a-8b)(7a-8b)
=2(7a-8b)²

Answer 3

解：(3a-4b)(7a-8b)-(11a-12b)(8b-7a)
=(3a-4b)(7a-8b)+(11a-12b)(7a-8b)
=(7a-8b)(3a-4b+11a-12b)
=(7a-8b)(14a-16b)
=2(7a-8b)(7a-8b)
=2(7a-8b)²

Answer 4

原式=(3a-4b)(7a-8b)+(11a-12b)(7a-8b)
=[(3a-4b)+(11a-12b)](7a-8b)
=(14a-16b)（7a-8b)
=2(7a-8b)(7a-8b)
=2(7a-8b)^2

Answer 5

(3a-4b)(7a-8b)-(11a-12b)(8b-7a)
=>(3a-4b)(7a-8b)-(11a-12b)(-(7a-8b)) //负号提前
=>(3a-4b)(7a-8b)+(11a-12b)(7a-8b)
=>(7a-8b)(3a-4b+11a-12b)
=>(7a-8b)(14a-16b) // (14a-16b)=2(7a-8b)
=>2(7a-8b)^2