数字电路：化简逻辑函数 Y=AB + AC' + B'C + BC' + B'D + BD' +ADE(F + G)
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解：Y=AB + AC' + B'C + BC' + B'D + BD' +ADE(F + G)
=AB+ AC'+B'D + B'C + BC' + BD' +ADE(F + G)
=A(B'C)'+B'D+B'C + BC' + BD' +ADE(F + G)
=A+B'D+B'C + BC' + BD'
=A+B'D+B'C + BC' + BD' +C'D
=A+B'C + BD' +C'D
如有意见，欢迎讨论，共同学习；如有帮助，请选为满意回答！
=AB+ AC'+B'D + B'C + BC' + BD' +ADE(F + G)
=A(B'C)'+B'D+B'C + BC' + BD' +ADE(F + G)
=A+B'D+B'C + BC' + BD'
=A+B'D+B'C + BC' + BD' +C'D
=A+B'C + BD' +C'D
如有意见，欢迎讨论，共同学习；如有帮助，请选为满意回答！
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