Question

定义一个10位的数组，array＝｛1，2，3，4，5，6，7，8，9，10｝，怎样实现输出来是随机排列的

Answer 1

//利用随机数
# include "stdio.h"
# include "stdlib.h"
int main(void)
{
int array[]={1,2,3,4,5,6,7,8,9,10};
int i,j;
for (i=0; i<=9; ++i)
{
j = rand() % 10;
printf("%d ",array[j]);
}
printf("\n");
return 0;
}
/*
输出结果：
------------------------
2 8 5 1 10 5 9 9 3 5
Press any key to continue
------------------------------
*/

追问

随机出的数不能重复

追答

# include "stdio.h"
# include "stdlib.h"
int main(void)
{
int array[]={1,2,3,4,5,6,7,8,9,10};
int i,j;
for (i=0; i<=9; ++i)
{
j = rand() % (10-i);
printf("%d ",array[j]);
int k;
for(k=j;k<10;++k)
array[k]=array[k+1];
}
printf("\n");
return 0;
}
/*
输出结果：
------------------------
2 10 8 7 9 6 4 1 3 5
Press any key to continue
------------------------------
*/

Answer 2

必须是1到10的不重复数吗？
Sub test()
Dim arr(1 To 10)
Dim d As Object
Set d = CreateObject("scripting.dictionary")
Do While x < 10
i = Int(Rnd() * 10 + 1)
If Not d.exists(i) Then
x = x + 1
d(i) = x
arr(x) = i
End If
Loop
Range("A1").Resize(10, 1) = Application.Transpose(arr)
End Sub