Question

因式分解：[x（x²y²-xy）-y（x²-x³y）]÷3x²y

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速度，13:40之前有奖励！

Answer 1

原式=[x²y(xy-1)-x²y(1-xy)]÷3x²y
=(xy-1-1+xy)÷3
=(2xy+2)/3

Answer 2

[x（x²y²-xy）-y（x²-x³y）]÷3x²y

=[x³y²-x²y-yx²＋x³y²]÷3x²y
=[2x³y²-2x²y]÷3x²y
=【2xy-2】/3

Answer 3

：[x（x²y²-xy）-y（x²-x³y）]÷3x²y
=（x³y²-x²y-x²y+x³y²）÷3x²y
=（2x³y²-2x²y）÷3x²y
=2x²y（xy-1）÷3x²y
=2/3（xy-1）

Answer 4

[x（x²y²-xy）-y（x²-x³y）]÷3x²y

=[x²y（xy-1）-x²y（1-xy）]÷3x²y
=x²y[（xy-1）-（1-xy）]÷3x²y
=x²y[2（xy-1）]÷3x²y
=2（xy-1)/3