Question

先化简，再求值：2x^2(x^2-x+1)-x(2x^3-10x^2-2x-3),其中x=-二分之一

11点之前回答有v +

Answer 1

2x²(x²-x+1)-x(2x³-10x²-2x-3)
=2x^4-2x³+2x²-2x^4+10x³+2x²+3x
=8x³+4x²+3x
=8*(-1/2)³+4*(-1/2)²+3*(-1/2)
=8*(-1/8)+4*(1/4)+3*(-1/2)
=-1+1+(-3/2)
=-3/2