Question

已知X=根号3+2,Y=根号3-2.求X平方+2XY+Y的平方..X平方Y+xy的平方

Answer 1

X^2+2XY+Y^2=(X+Y)^2=12
X^2Y+xy^2=xy(X+Y)=-2√3

追问

详细过程

追答

xy=(√3+2)(√3-2)=3-4=-1
x+y=(√3+2)+(√3-2)=2√3

追问

是要=12的过程和=2倍根号3的过程

追答

x=(√3+2),y=(√3-2)
xy=(√3+2)(√3-2)=3-4=-1
x+y=(√3+2)+(√3-2)=2√3
X^2+2XY+Y^2=(X+Y)^2=(2√3)^2=12
X^2Y+xy^2=xy(X+Y)=-1*2√3=-2√3