
已知a是方程x^2-3x+1=0的根,试求2a^2-5a-2+3/(a^2-1) 15
2个回答
展开全部
题目应是 已知a是方程x^2-3x+1=0的根,试求2a^2-5a-2+3/(a^2+1)
已知a是方程x^2-3x+1=0的根,
a^2-3a+1=0
a^2=3a-1
2a^2-5a-2+3/(a^2+1)
=2(3a-1)-5a-2+3/(3a+1-1)
=6a-2-5a-2+3/(3a)
=a-4+1/a
=(a^2-4a+1)/a
=(3a-1-4a+1)/a
=(-a)/a
=-1
已知a是方程x^2-3x+1=0的根,
a^2-3a+1=0
a^2=3a-1
2a^2-5a-2+3/(a^2+1)
=2(3a-1)-5a-2+3/(3a+1-1)
=6a-2-5a-2+3/(3a)
=a-4+1/a
=(a^2-4a+1)/a
=(3a-1-4a+1)/a
=(-a)/a
=-1
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询