(16x-13)/(4x-3)+(40x-43)/(8x-9)=(32x-30)/(8x-7)+(20x-24)/(4x-5)
2个回答
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解:
(16x-13)/(4x-3)+(40x-43)/(8x-9)=(32x-30)/(8x-7)+(20x-24)/(4x-5)
4-1/(4x-3)+5+2/(8x-9)=4-2/(8x-7)+5+1/(4x-5)
2/(8x-9)+2/(8x-7)=1/(4x-3)+1/(4x-5)
2(8x-9+8x-7)/[(8x-9)(8x-7)]=(4x-3+4x-5)/[(4x-3)(4x-5)]
2(16x-16)/[(8x-9)(8x-7)]=(8x-8)/[(4x-3)(4x-5)] 其中x=1时等式恒成立 若x≠1时可化为
4(4x-3)(4x-5)=(8x-9)(8x-7)
64x²-128x+60=64x²-128x+63
等式不成立
所以方程的解为x=1
(16x-13)/(4x-3)+(40x-43)/(8x-9)=(32x-30)/(8x-7)+(20x-24)/(4x-5)
4-1/(4x-3)+5+2/(8x-9)=4-2/(8x-7)+5+1/(4x-5)
2/(8x-9)+2/(8x-7)=1/(4x-3)+1/(4x-5)
2(8x-9+8x-7)/[(8x-9)(8x-7)]=(4x-3+4x-5)/[(4x-3)(4x-5)]
2(16x-16)/[(8x-9)(8x-7)]=(8x-8)/[(4x-3)(4x-5)] 其中x=1时等式恒成立 若x≠1时可化为
4(4x-3)(4x-5)=(8x-9)(8x-7)
64x²-128x+60=64x²-128x+63
等式不成立
所以方程的解为x=1
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