
展开全部
[(3a-7)^2-(a+5)^2]/(4a-24)
=[(9a²-42a+49)-(a²+10a+25)]/(4a-24)
=(8a²-52a+24)/[4(a-6)]
=(a-6)(8a-4)/[4(a-6)]
=(8a-4)/4
=2a-1
=2*(1/50)-1
=1/25-1
=-24/25
=[(9a²-42a+49)-(a²+10a+25)]/(4a-24)
=(8a²-52a+24)/[4(a-6)]
=(a-6)(8a-4)/[4(a-6)]
=(8a-4)/4
=2a-1
=2*(1/50)-1
=1/25-1
=-24/25
展开全部
[(3a-7)^2-(a+5)^2]/(4a-24),
=[(3a-7)+(a+5)][(3a-7)-(a+5)]/(4a-24),
=(4a-2)(2a-12)/(4a-24)
=4(2a-1)(a-6)/4(a-6)
=2a-1
=2/50-1
=-24/25
=[(3a-7)+(a+5)][(3a-7)-(a+5)]/(4a-24),
=(4a-2)(2a-12)/(4a-24)
=4(2a-1)(a-6)/4(a-6)
=2a-1
=2/50-1
=-24/25
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
解:[(3a-7)^2-(a+5)^2]/(4a-24),
=[(3a-7)+(a+5)][(3a-7)-(a+5)]/(4a-24),
=(4a-2)(2a-12)/(4a-24)
=4(2a-1)(a-6)/4(a-6)
=2a-1
=2/50-1
=-24/25
=[(3a-7)+(a+5)][(3a-7)-(a+5)]/(4a-24),
=(4a-2)(2a-12)/(4a-24)
=4(2a-1)(a-6)/4(a-6)
=2a-1
=2/50-1
=-24/25
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询