先化简,再求值[x+2-5/(x-2)]/[(x-3)/(x-2)],其中a=-3
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先化简,再求值[x+2-5/(x-2)]/[(x-3)/(x-2)],其中 x=-3 ----不是a
[x+2-5/(x-2)]/[(x-3)/(x-2)]
=[(x+2)(x-2)/(x-2)-5/(x-2)]/[(x-3)/(x-2)]
=[( x^2-4)/(x-2)-5/(x-2)]/[(x-3)/(x-2)]
=[(x^2-9)/(x-2)]/[(x-3)/(x-2)]
=[(x+3)(x-3)/(x-2)]*[(x-2)/(x-3)]
=x+3
= -3+3
= 0
[x+2-5/(x-2)]/[(x-3)/(x-2)]
=[(x+2)(x-2)/(x-2)-5/(x-2)]/[(x-3)/(x-2)]
=[( x^2-4)/(x-2)-5/(x-2)]/[(x-3)/(x-2)]
=[(x^2-9)/(x-2)]/[(x-3)/(x-2)]
=[(x+3)(x-3)/(x-2)]*[(x-2)/(x-3)]
=x+3
= -3+3
= 0
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