Question

四道分解因式，求过程，拜托咯！！！

Answer 1

1、原式=XY(X^2Y^2-2XY+1)=XY(XY-1)^2，
2、原式=［(X^2+Y^2)+2XY］［(X^2+Y^2)-2XY］
=(X+Y)^2(X-Y)^2
3、原式=［3(X-Y)^2+7］^2=(3X-3Y+7)^2
4、原式=［4(X+Y)+5(X-Y)］^2=(9X-Y)^2。

Answer 2

分解因式：()xy–(x-y)()-(a-b)+(a-b) 8.分解因式：()-ma+ma-ma()a(x-y)+b(y-x)9、写一个多项式，再把它分解因式(要求：多项式含有字母m和n，系数、次数不限，并能先用提取公因式法再用公式法分解).

Answer 3

1，
x³y³-2x^2y^2+xy
=xy(x²y²-2xy+1)
=xy(xy-1)²
2,
(x²+y²)²-4x²y²
=[(x²+y²)+2xy][(x²+y²)-2xy]
=(x+y)²(x-y)²
3,
9(x-y)²+42(x-y)+49
=[3(x-y)]²+42(x-y)+7²
=[3(x-y)+7]²
=(3x-3y+7)²
4,
16(x+y)²+40(x+y)(x-y)+25(x-y)²
=[4(x+y)]²+40(x+y)(x-y)+[5(x-y)]²
=[4(x+y)+5(x-y)]²
=(4x+4y+5x-5y)²
=(9x-y)²

Answer 4

1、=xy（x²y²-2xy+1）
=xy（xy+1）²
2、=x^4+2x^2y^2+y^4-4x^2y^2
=x^4-2x^2y^2+y^4
=(x²-y²)²
3、=【3（x-y）】²+42（x-y）+7²
=【3（x-y）+7】²
=（3x-3y+7）²
4、=[4(x+y)]²+40（x+y）（x-y）+[5（x-y）]²
=【4（x+y）+5（x-y）】²
=（9x-y）²

Answer 5

X³Y³-2X²Y²+XY
=XY(X²Y²-2XY+1)
=XY(XY-1)²
﹙X²+Y²﹚²﹣4X²Y²
=﹙X²+Y²﹚²－﹙2XY﹚²
=﹙X²﹢Y²﹢2XY﹚﹙X²﹢Y²-2XY﹚
=﹙X﹢Y﹚²﹙X-Y﹚²
9(x-y)²+42(x-y)+49
=[3(x-y)]²+42(x-y)+7²
=[3(x-y)+7]²
=(3x-3y+7)²
16(x+y)²+40(x+y)(x-y)+25(x-y)²
=[4(x+y)]²+40(x+y)(x-y)+[5(x-y)]²
=[4(x+y)+5(x-y)]²
=(4x+4y+5x-5y)²
=(9x-y)²