Question

分解因式，十万火急

Answer 1

x³-9x
=x(x²-9)
=x(x+3)(x-3)

16x^4-1
=(4x²+1)(4x²-1)
=(4x²+1)(2x-1)(2x+1)

6xy²-9x²y-y³
=y(6xy-9x²-y²)
=-y(9x²-6xy+y²)
=-y(3x-y)²

(2a-b)²+8ab
=4a²-4ab+b²+8ab
=4a²+4ab+b²
=(2a+b)²

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Answer 2

1 x(x^2-3^2)=x(x+3)(x-3)

2 =(2x)^4-1
=[(2x)^2+1][(2x)^2-1]
=[(2x)^2+1](2x+1)(2x-1)

3 =y(6xy-9x^2-y^2)
=-y(y^2-6xy+9x^2)
=-y(y-3x)(y-3x)

4 =4a^2-4ab+b^2+8ab
=4a^2+4ab+b^2
=(2a+b)^2

Answer 3

（1）原式=x（x^2-9）
=x(x+3)(x-3)
(2)原式=（4x^2-1）(4x^2+1)
=(2x+1)(2x-1)(4x^2+1)
(3)原式=y(6xy-9x^2-y^2)
=-y(3x-y)^2
(4)原式=4a^2-4ab+b^2+8ab
=4a^2+4ab+b^2
=(2a+b)^2

Answer 4

解：1.原式=x(x^2-9)=x(x+3)(x-3)
2.原式=(4x^2+1)(4x^2-1)=(4x^2+2)(2x+1)(2x-1)
3.原式=-y(-6xy+9x^2+y^2)=-y(y-3x)^2
4.原式=4a^2-4ab+b^2+8ab=4a^2+4ab+b^2=(2a+b)^2