Question

设函数f(x)=3sin(ωx+π/6),ω＞0,且以π/2为最小正周期

当x∈[-π/12,π/6]时,求f(x)的最值

Answer 1

以π/2为最小正周期，那显然ω=4.
x∈[-π/12,π/6]，则ωx+π/6∈[-π/6,5π/6]。
最大值是3，当ωx+π/6=π/2时取到
最小值是-1.5，当ωx+π/6=-π/6时取到