(tan10度-根号3]×(cos1O度/sin50度],请化简上式.
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解答：
(tan10度-根号3]×(cos1O度/sin50度],
=(sin10°/cos10°-√3)*cos10°/sin50°
=(sin10°-√3cos10°)/sin50°
=2[sin10°*(1/2)-cos10°*(√3/2)]/sin50°
=2(sin10°cos60°-cos10°sin60°)/sin50°
=2sin(10°-60°)/sin50°
=-2sin50°/sin50°
=-2
(tan10度-根号3]×(cos1O度/sin50度],
=(sin10°/cos10°-√3)*cos10°/sin50°
=(sin10°-√3cos10°)/sin50°
=2[sin10°*(1/2)-cos10°*(√3/2)]/sin50°
=2(sin10°cos60°-cos10°sin60°)/sin50°
=2sin(10°-60°)/sin50°
=-2sin50°/sin50°
=-2
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