Question

化简求值[（x+y）²-（x-y)²+4x²y²]÷4xy，x=（√2）°，y=2

那个°是零次方

Answer 1

解：原式=（x²+2xy+y²-x²+2xy-y²+4x²y²）÷4xy
=（4xy+4x²y²）÷4xy
=1+xy
当x=1,，y=2时，
原式=1+2=3

Answer 2

x=(√2)^0 =1

[(x+y)²-(x-y)²+4x²y²]÷(4xy)
=(x²+y²+2xy-x²+2xy-y²+4x²y²)/(4xy)
=(4xy+4x²y²)/(4xy)
=(4xy)(1+xy)/(4xy)
=1+xy
=1+1×2
=3

Answer 3

x=（√2）°=1，y=2
[（x+y）²-（x-y)²+4x²y²]÷4xy
=[x²+2xy+y²-x²+2xy-y²+4x²y²]÷4xy
=(4xy+4x²y²)÷4xy
=1+xy
=1+1×2
=3

Answer 4

∵[（x+y）²-（x-y)²+4x²y²]÷4xy
∴[(x+y+x-y)(x+y-x+y)+4x²y²]÷4xy
=(4xy+4x²y²)÷4xy
=1+xy

∵x=（√2）°=1,y=2
∴原式=1+1×2=1+2=3

Answer 5

这个很简单，初二的的题目吧，多看一下书上的公式x=（√2）°=1，y=2
[（x+y）²-（x-y)²+4x²y²]÷4xy
=[x²+2xy+y²-x²+2xy-y²+4x²y²]÷4xy
=(4xy+4x²y²)÷4xy
=1+xy
=1+1×2
=3

Answer 6

原式=[(x+y+x-y)(x+y-x+y)+4x^2*y^2]/4xy
=(4xy+4x^2*y^2)/4xy
=1+xy
代数
=1+(√2)^0*2
=1+1*2
=3