Question

初二数学题.要过程

Answer 1

[3(x-y)^4(x+y)^5-6(x-y)^3(x+y)^4]/[3(x-y)^2(x+y)^3]
=3(x-y)^4(x+y)^5/[3(x-y)^2(x+y)^3]-6(x-y)^3(x+y)^4/[3(x-y)^2(x+y)^3]
=(x-y)^2(x+y)^2-2(x-y)(x+y)
=(x-y)(x+y)(x^2-y^2-2)

或者直接对分子合并同类项，再做，答案也是一样的~
见下：
[3(x-y)^4(x+y)^5-6(x-y)^3(x+y)^4] / [3(x-y)^2(x+y)^3]

=3(x-y)^3(x+y)^4(x^2-y^2-2) / 3(x-y)^2(x+y)^3
=(x-y)(x+y)(x^2-y^2-2)

x^2表示x的平方，x^3表示x的三次方，以此类推等等。

追问

最后一步不能在化简了么？

追答

是的，因为x^2-y^2-2已经在初中的范围内已经不能再化简了~
这个是最简结果呢~

Answer 2

3（X-Y)^2(X+y)^3((x-y)^2(x+y)^2-2（x-y)(x+y))/(3(x-y)^2(x+y0^3）=（x-y)^2(x+y)^2-2(x-y)(x+y)=(x^2-y^2)^2-2(x^2-y^2)=(x-y)(x+y)(x^2-y^2-2)

Answer 3

我擦 不会