Question

从键盘输入一个字符串,将其中的所有数字字符抽出,按原顺序组成一个新串并输出AB93CD96kg,则输出新串9396

急！！！！！

Answer 1

public class Demo {
/**
* @param args
*/
public static void main(String[] args) {
String s="ad 90 s-=-3 aA";
StringBuilder sb=new StringBuilder(s);
StringBuilder isNum=new StringBuilder();
for(int i=0;i<sb.length();i++){
char c=sb.charAt(i);
if(Character.isDigit(c)){
isNum.append(c);
}
}
System.out.println("数字为:"+isNum.toString());
}
}

Answer 2

public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
while(true){
System.out.println("请输入：");
String s = scanner.next();
String str = s.replaceAll("[a-zA-Z]", "");
System.out.println(str.trim());
}
}

Answer 3

var c:char;
begin
repeat
read(c);
if c in ['0'..'9'] then write(c)
until eoln;
writeln;
end.