Question

(x+2)的平方+2(x+2)(x-2)-3(x+2)(x-1)

Answer 1

(x+2)^2+2(x+2)(x-2)-3(x+2)(x-1)
=(x^2+4x+4)+2(x^2-4)-3(x^2+x-2)
=x^2+4x+4+2x^2-8-3x^2-3x+6
=(x^2+2x^2-3x^2)+(4x-3x)+(4-8+6)
=x+2

或者：
(x+2)的平方+2(x+2)(x-2)-3(x+2)(x-1)

=(x+2)*[(x+2)+2(x-2)-3(x-1)]
=(x+2)*(x+2+2x-4-3x+3)
=(x+2)*1
=x+2

Answer 2

(x+2)的平方+2(x+2)(x-2)-3(x+2)(x-1)
=(x²+4x+4)+(2x²-8)-3(x²+x-2)
=x²+4x+4+2x²-8-3x²-3x+6
=x+2

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Answer 3

(x+2)的平方+2(x+2)(x-2)-3(x+2)(x-1)
=(x+2)[(x+2)+2(x-2)-3(x-1)]
=(x+2)(x+2+2x-4-3x+3)
=(x+2)*1
=x+2

Answer 4

是化简吗？
（x+2）²+2（x＋2﹚﹙x－2﹚－3﹙x＋2﹚﹙x－1﹚
＝﹙x²＋4x＋4﹚＋2﹙x²－4﹚－3﹙x²＋x－2﹚

＝x＋10

Answer 5

(x+2)^2+2(x+2)(x-2)-3(x+2)(x-1)
=(x-2)[(x+2)+2(x-2)-3(x-1)]
=x-2