Question

c++关于用类作为类中函数的参数问题

我写了一个头文件和一个CPP文件，请问错误在哪里？
MyPoint.h:
class MyPoint
{
public:
MyPoint();
MyPoint(double x,double y,double z);
double getX();
double getY();
double getZ();
double distance(MyPoint point());

private:
double x;
double y;
double z;
};

MyPoint.cpp:
#include"MyPoint.h"#include<cmath>
MyPoint::MyPoint()
:x(0),y(0),z(0)
{
}

MyPoint::MyPoint(double x,double y,double z)
{
this->x=x;
this->y=y;
this->z=z;
}

double MyPoint::getX()
{
return x;
}

double MyPoint::getY()
{
return y;
}

double MyPoint::getZ()
{
return z;
}

double MyPoint::distance(class MyPoint point())
{
double a=(x-point.getX())+(y-point.getY())+(z-point.getZ());
return sqrt(a);
}

Answer 1

double distance(MyPoint point());

定义类内部的函数不需要构造对象，把point后面的括号去掉
double distance(MyPoint point);

当然写成：double distance(const MyPoint &point) const;更好

double MyPoint::distance(class MyPoint point())

这个去掉class，point后面的括号
double MyPoint::distance(MyPoint point)

同样变成：double MyPoint::distance(const MyPoint &point) const更好

Answer 2

求两点间距离的公式用错了，参数貌似也不对，建议改成这样:
double MyPoint::distance(MyPoint &mp) {
double a = (x - mp.getX()) * (x - mp.getX()) + (y - mp.getY())*(y - mp.getY()) + (z - mp.getZ()) * (z - mp.getZ());;
return sqrt(a);
}

Answer 3

　MyPoint.h:

　　double distance(MyPoint point());

改为
doubledistance(MyPoint point);

　　MyPoint.cpp:

　　 double MyPoint::distance(class MyPoint point())

改为
doubleMyPoint::distance(MyPoint point)

另外：这个方法的算法不太对。