Question

求X1和X2的范围，和用MATLAB的编程过程

50<X2<X1<700，
t1=(700+x1)/2,
t2=(x1+x2)/2,
t3=(x2+50)/2,
B1=0.294+0.212*t1/1000,
B2=0.03032+0.1567*t2/1000,
B3=0.131+0.23*t3/1000,
Q=650/(0.115/B1+0.08/B2+0.115/B3+1/11.44),
R1=700-Q*0.115/B1,
R2=R1-Q*0.08/B2,
R3=R2-Q*0.115/B3<70;
A1=|(R1-X1)/X1|<0.05;
A2=|(R2-X2)/X2|<0.05;

Answer 1

你的意思是根据
R3=R2-Q*0.115/B3<70;
A1=|(R1-X1)/X1|<0.05;
A2=|(R2-X2)/X2|<0.05;
这三个条件解出X2，X1的范围？

追问

是啊

追答

clear;
clc;
X2=50:0.001:700;
X1=50:0.001:700;
t1=(700+X1)/2;
t2=(X1+X2)/2;
t3=(X2+50)/2;
B1=0.294+0.212*t1/1000;
B2=0.03032+0.1567*t2/1000;
B3=0.131+0.23*t3/1000;

S=ones(1,650001)*1/11.44;
Q=650./(0.115./B1+0.08./B2+0.115./B3+S);
R1=700-(Q*0.115)./B1;
R2=R1-(Q*0.08)./B2;

R3=R2-(Q*0.115)./B3;
A1=abs((R1-X1)/X1);
A2=abs((R2-X2)/X2);

R3=find(R3<70);
A1=find(A1<0.05);
A2=find(A2<0.05);

程序是这个不过你的式子，可能有问题。R3有解，A1，A2是空集。