Question

i^(1-i)怎么求解- -谢谢

Answer 1

i^(1-i)
=e^[lni^(1-i)]
=e^[(1-i)*lni]
=e^[(1-i)*π/2*i]
=e^(π/2)*e^(πi/2)
=e^(π/2)*[cos(π/2)+i*sin(π/2)]
=i*e^(π/2) 。