
整式的除法计算
1.(-3/2)^0/(-3/2)^22.(-2ab)^5/ab^43.(2x^2y)^3*(-7xy^2)/(14x^4*y^4)4.(3/2)(2a+b)^3/(2/...
1.(-3/2)^0/(-3/2)^2
2.(-2ab)^5/ab^4
3.(2x^2y)^3*(-7xy^2)/(14x^4*y^4)
4.(3/2)(2a+b)^3/(2/3)(2a+b)^2 展开
2.(-2ab)^5/ab^4
3.(2x^2y)^3*(-7xy^2)/(14x^4*y^4)
4.(3/2)(2a+b)^3/(2/3)(2a+b)^2 展开
1个回答
展开全部
1.(-3/2)^0/(-3/2)^2=(-3/2)^﹙﹣2﹚=﹙﹣2/3﹚^2=4/9
2.(-2ab)^5/ab^4=﹣32a^5b^5÷ab^4=﹣32a^4b
3.(2x^2y)^3*(-7xy^2)/(14x^4*y^4)=8x^6y^3*(-7xy^2)÷14x^4y^4=﹣4x^3y
4.(3/2)(2a+b)^3/(2/3)(2a+b)^2=9/4﹙2a+b﹚
2.(-2ab)^5/ab^4=﹣32a^5b^5÷ab^4=﹣32a^4b
3.(2x^2y)^3*(-7xy^2)/(14x^4*y^4)=8x^6y^3*(-7xy^2)÷14x^4y^4=﹣4x^3y
4.(3/2)(2a+b)^3/(2/3)(2a+b)^2=9/4﹙2a+b﹚
追问
(-ab)^5/ab^4怎么做?
追答
(-ab)^5/ab^4=-a^5b^5÷ab^4=﹣a^4b
(-ab)^5/﹙ab﹚^4=﹣﹙ab﹚^5÷﹙ab﹚^4=﹣﹙ab﹚^1=﹣ab
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