Question

求数学大神解答。。。求过程

lim [(1+tan x)/(1+sin x)]^(1/x^3) x趋于零

Answer 1

设y=[(1+tanx)/(1+sinx)]^(x^3)
lny=(1/x^3)ln[(1+tanx)/(1+sinx)]
lim[x→0] lny
=lim[x→0] (1/x^3)ln[(1+tanx)/(1+sinx)]
=lim[x→0] (1/x^3)ln[(1+sinx-sinx+tanx)/(1+sinx)]
=lim[x→0] (1/x^3)ln[1+(tanx-sinx)/(1+sinx)]
ln[1+(tanx-sinx)/(1+sinx)]等价于(tanx-sinx)/(1+sinx)
=lim[x→0] (1/x^3)(tanx-sinx)/(1+sinx)
=lim[x→0] (tanx-sinx)/[x^3(1+sinx)]
=lim[x→0] tanx(1-cosx)/[x^3(1+sinx)]
tanx等价于x，1-cosx等价于x^2/2
=lim[x→0] x*(x^2/2)/[x^3(1+sinx)]
=lim[x→0] 1/2(1+sinx)]
=1/2

因此lim[x→0] lny=1/2，则lim[x→0] y=e^(1/2)

看看有没有问题~

Answer 2

lim [(1+tan x)/(1+sin x)]^(1/x^3) x趋于零=1

Answer 3

哎！与大神无缘