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初二数学:若1/x-1/y=3,试求(2x-3xy-2y)/(x-2xy-y)的值。
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1/x-1/y=3
所以:y-x=3xy
(2x-3xy-2y)/(x-2xy-y)
=【2(x-y)-3xy】/【(x-y)-2xy】
= (-6xy-3xy)/(-3xy-2xy)
= -9xy/(-5xy)
=9/5
所以:y-x=3xy
(2x-3xy-2y)/(x-2xy-y)
=【2(x-y)-3xy】/【(x-y)-2xy】
= (-6xy-3xy)/(-3xy-2xy)
= -9xy/(-5xy)
=9/5
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