分解因式a²(a-b)+b²(b-a)
2个回答
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a²(a-b)+b²(b-a)
=a²(a-b)-b²(a-b)
=(a-b)(a²-b²)
=(a-b)(a-b)(a+b)
=(a-b)²(a+b)
8(x²-2y²)-x(7x+y)+xy
=8x²-16y²-7x²-xy+xy
=x²-16y²
=(x-4y)(x+4y)
x³+x²y-xy²-y³
=(x³-y³)+x²y-xy²
=(x-y)(x²-xy+y²)+xy(x-y)
=(x-y)(x²-xy+y²+xy)
=(x-y)(x²+y²)
=a²(a-b)-b²(a-b)
=(a-b)(a²-b²)
=(a-b)(a-b)(a+b)
=(a-b)²(a+b)
8(x²-2y²)-x(7x+y)+xy
=8x²-16y²-7x²-xy+xy
=x²-16y²
=(x-4y)(x+4y)
x³+x²y-xy²-y³
=(x³-y³)+x²y-xy²
=(x-y)(x²-xy+y²)+xy(x-y)
=(x-y)(x²-xy+y²+xy)
=(x-y)(x²+y²)
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