Question

php弹出对话框之后再返回上级页面怎么实现

3

Answer 1

可以用JS实现跳转，代码如下：

echo "<script language=javascript>alert('删除成功！');history.back();</script>";

Answer 2

echo "<script>alert('弹出来！');location.href='想要返回的url';</script>";