Question

cos(π-α)tan(2π-α)tan(π-α)/sin(π+α) 化简

Answer 1

（cos（π-α）tan（2π-α)tan（π-α））/sin（π+α）=(-cosα) (-tanα) (-tanα)/(-sinα)=tanα
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Answer 2

cos(π-α)tan(2π-α)tan(π-α)/sin(π+α)
=-cosa*(-tana)*(-tana)/(-sina)
=cosa*tana^2/sina
=tana^2/(sina/cosa)
=tana^2/tana
=tana