Question

计算：1.三次根号下27+2倍根号3-|1-根号3|

2.|根号2-根号5|+根号下[（根号27)-1]^2-根号下[（根号5）-3]^2

Answer 1

三次根号下27+2倍根号3-|1-根号3|
=3+2√3-(√3-1)
=4+√3

|根号2-根号5|+根号下[（根号27)-1]^2-根号下[（根号5）-3]^2
=√5-√2+√(3-1)^2-(3-√5)
=√5-√2+2-3+√5
=2√5-√2-1

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追问

不好意思，我的第二题打错了，是：|根号2-根号5|+根号下[（根号2)-1]^2-根号下[（根号5）-3]^2

追答

|根号2-根号5|+根号下[（根号2)-1]^2-根号下[（根号5）-3]^2
=√5-√2+√(√2-1)^2-(3-√5)
=√5-√2+(√2-1)-3+√5
=√5-√2+√2-1-3+√5
=2√5-4