Question

已知y=x²-x分之x÷x²-2x+1分之x²-1-x+1分之2。当x为何值时,y的值为3分之1?

已知（y=x²-x分之x）÷（x²-2x+1分之x²-1）-（x+1分之2）。当x为何值时，y的值为3分之1?

Answer 1

y=x/x(x-1)÷(x+1)(x-1)/(x-1)²-2/(x+1)
=1/(x-1)×(x-1)/(x+1)-2/(x+1)

=1/(x+1)-2/(x+1)

=-1/(x+1)=1/3
所以x+1=-3
x=-4

Answer 2

化简一下应该就是这样的：
y=[x*(x²-2x+1)]/[(x²-x)*(x²-1)]-2/(x+1)
=[x*(x-1)²]/[x*(x-1)*(x+1)(x-1)]-2/(x+1)
=1/(x+1)-2/(x+1)
=-1/(x+1)
所以，当x=-4时，y=1/3