Question

c++编写一个简单的程序

要求用户输入一组数。输出信息说明其中有多少个负数？

Answer 1

#include <iostream>
using namespace std;
int main()
{
int count = 0;
int num;
cout<<"输入一组数，以Ctrl+Z结束"<<endl;
while(cin>>num)
{
if(num<0)
{
++count;
}
}
cout<<"负数有"<<count<<"个"<<endl;
return 0;
}

Answer 2

class qq
{
private:
int* a;
public:
int ge;
in
void qq(int *x)
{
a=x;
ge=0;
}
int geshu(void)
{
for(i=0;i<=sizaof(a);i++)
{
if ((*(a+i))<0)
{
ge+=1
}
}

}

}
main()
{
1.获得数组s,根据你的需要填
int *ps=s;
qq t(ps);
t.geshu()
t.ge=?就是你需要的

}
可以改进一下，可能有个地方错了，你自己改吧

Answer 3

#define INPUT_NUMBER 5//it can appoint the total input numbers #include <stdio.h>
int main()
{
int a[INPUT_NUMBER];
int i;
int total;
printf("please input %d numbers!\n", INPUT_NUMBER);

for(i=0;i<INPUT_NUMBER;i++)
{
scanf("%d",a+i);// also here you can judge it is negative or not
}
total = 0;
for(i=0;i<INPUT_NUMBER;i++)
{
if(a[i]<0){
total += 1;
}
}

printf("you just input %d negative numbers!\n", total);
return 0;
}