Question

初一数学题 求详细解答

Answer 1

同学你好，解析：
（1）原方程化为：x^2-(c+m/c)x+m=0（x不等于0）
x=(c+m/c+√(c^2+m^2/c^2+2m-4m))/2或x=(c+m/c-√(c^2+m^2/c^2+2m-4m))/2
得x1=(c+m/c+c-m/c)/2=c，x2=(c+m/c-c+m/c)/2=m/c
(2)原方程化为：（x-1）+2/(x-1)=a-1+2/(a-1)
则x-1=a-1或者x-1=2/(a-1)
得x1=a,x2=(a+1)/(a-1)
同学你好，如果你对本题还有疑问，请在聊聊中联系我，我将详细为你解答。祝你学习进步！