Question

计算题(详细过程)

根号12×根号3分之1+(根号3)º
4根号2分之1+3根号3分之1-根号8
(2-根号3)的2012次方(2+根号3)的2013次方-2|-2分之根号3|-(-根号2)º

Answer 1

1、原式=根号(12×1/3) +1
=根号4 +1
=2+1
=3

2、原式= 2根号2+根号3 -2根号2
=根号3

3、=[(2-根号3)(2+根号3)]的2012次方 ×(2+根号3) -根号3-1
=2+根号3-根号3-1
=1

Answer 2

√12×√(1/3)+(√3)º
=√[12×(1/3)]+1
=√4+1
=2+1
=3

4√(1/2)+3√(1/3)-√8
=4√[(1/2)²×2]+3√[(1/3)²×3]-√(2²×2)
=[4×(1/2)]√2+[3×(1/3)]√3-2√2
=2√2+√3-2√2
=√3

[(2-√3)^2012][(2+√3)^2013]-2|-√3/2|-(-√2)º
=[(2-√3)^2012][(2+√3)^2012](2+√3)-2×(√3/2)-1
={[(2-√3)(2+√3)]^2012}(2+√3)-√3-1
={[2²-(√3)²]^2012}(2+√3)
=[(4-1)^2012](2+√3)-√3-1
=(1^2012)(2+√3)-√3-1
=1×(2+√3)-√3-1
=2+√3-√3-1
=1

Answer 3

234695/(12346²-12345×312347)
=234695/[12346²-(12346-1)×(12346+1)]
=234695/[12346²-(12346²-1)]
=234695/1
=234695
请采纳。