Question

(x-1)(x+2)(x-3)(x-4)+24分解因式等于？

Answer 1

应该是"(x-1)(x-2)(x-3)(x-4)-24"吧!

(x-1)(x-2)(x-3)(x-4)-24
=[(x-1)(x-4)][(x-2)(x-3)]-24
=(x^2-5x+4)(x^2-5x+6)-24
=[(x^2-5x+5)-1][(x^2-5x+5)+1]-24
=(x^2-5x+5)^2-1-24
=(x^2-5x+5)^2-5^2
=(x^2-5x+5-5)(x^2-5x+5+5)
=(x^2-5x)(x^2-5x+10)
=x(x-5)(x^2-5x+10).

Answer 2

(x+1)(x+2)(x+3)(x+4)+1
=(x+1)(x+4)(x+2)(x+3)+1
=(x^+5x+4)(x^+5x+6)+1
另x^+5x=y,则原式变为
（y+4)(y+6)+1
=y^+10y+25
=(y+5)^
把x^+5x=y代入，得（x^+5x+5)^

Answer 3

?????楼上的怎么把减号全变成加号了？最后一个24也变成1了？？？？？