Question

大侠求 N日内换手率大于60小于100 且振幅大于50小于80 通达信公式

Answer 1

试试：
N:=15;
换手:=COUNT(RANGE(VOL/CAPITAL*100,2,10),N)=N-1;
振幅:=COUNT(RANGE((H-L)/REF(C,1)*100,5,20),N)=N-1;
换振:换手 AND 振幅;

Answer 2

换手率是N日累计吧？

sum(vol,n)/capital>0.6 and sum(vol,n)/capital<1 and hhv(h,n)/llv(l,n)-1>0.5 and hhv(h,n)/llv(l,n)-1<0.8;