计算2/(x-1)-1/(x+2)-2/(x+1)+1/(x-2)
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2/(x-1)-1/(x+2)-2/(x+1)+1/(x-2)
=[2/(x-1)-2/(x+1)]+[1/(x-2)-1/(x+2)]
=2[(x+1)-(x-1)]/(x-1)(x+1)+[(x+2)-(x-2)]/(x-2)(x+2)
=4/(x-1)(x+1)+4/(x-2)(x+2)
=4[(x-2)(x+2)+(x-1)(x+1)]/(x-1)(x+1)(x-2)(x+2)
=4（2x²-5）/(x-1)(x+1)(x-2)(x+2)
【数学辅导团】为您解答，不理解请追问，理解请及时选为满意回答！(*^__^*)谢谢！
2/(x-1)-1/(x+2)-2/(x+1)+1/(x-2)
=[2/(x-1)-2/(x+1)]+[1/(x-2)-1/(x+2)]
=2[(x+1)-(x-1)]/(x-1)(x+1)+[(x+2)-(x-2)]/(x-2)(x+2)
=4/(x-1)(x+1)+4/(x-2)(x+2)
=4[(x-2)(x+2)+(x-1)(x+1)]/(x-1)(x+1)(x-2)(x+2)
=4（2x²-5）/(x-1)(x+1)(x-2)(x+2)
【数学辅导团】为您解答，不理解请追问，理解请及时选为满意回答！(*^__^*)谢谢！
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2/(x-1)-1/(x+2)-2/(x+1)+1/(x-2)
=[2/(x-1)-2/(x+1)]+[1/(x-2)-1/(x+2)]
=4/(x^2-1)+4/(x^2-4)
=4(2x^2-5)/(x^2-1)(x^2-4)
=[2/(x-1)-2/(x+1)]+[1/(x-2)-1/(x+2)]
=4/(x^2-1)+4/(x^2-4)
=4(2x^2-5)/(x^2-1)(x^2-4)
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