Question

latex分段函数对齐问题求助

代码是：
\begin{equation}
le{v_{a,b}}\left({i,j} \right)=
\begin{cases}
\max ({i,j}) &{\min({i,j})=0}\\
\min
\begin{cases}
{le{v_{a,b}}\left( {i - 1,j} \right) + 1}\\
{le{v_{a,b}}\left( {i,j-1} \right) + 1} &{else}\\
{le{v_{a,b}}\left( {i - 1,j - 1} \right) + \left[ {{a_i} \ne {b_j}} \right]}\\
\end{cases}
\end{cases}
\end{equation}
请问如何将右边的min和else对齐？ 谢谢

Answer 1

\begin{equation}
le{v_{a,b}}\left({i,j} \right)=
\begin{cases}{cc}
\max ({i,j}) &{\min({i,j})=0}\\
\min
\begin{cases}{ll}
{le{v_{a,b}}\left( {i - 1,j} \right) + 1}\\
{le{v_{a,b}}\left( {i,j-1} \right) + 1} \\
{le{v_{a,b}}\left( {i - 1,j - 1} \right) + \left[ {{a_i} \ne {b_j}} \right]}
\end{cases}&{else}
\end{cases}
\end{equation}

Answer 2

代码太混乱且不合理，懒得改写了，你要对齐很简单，加了一句比较粗暴的语句即可实现，虽然很ugly，倒也可以应付你的文档了
\begin{equation}
le{v_{a,b}}\left({i,j} \right)=
\begin{cases}
\max ({i,j}) &{\hspace{-1.1cm}\min({i,j})=0}\\
\min
\begin{cases}
{le{v_{a,b}}\left( {i - 1,j} \right) + 1}\\
{le{v_{a,b}}\left( {i,j-1} \right) + 1} &{else}\\
{le{v_{a,b}}\left( {i - 1,j - 1} \right) + \left[ {{a_i} \ne {b_j}} \right]}\\
\end{cases}
\end{cases}
\end{equation}

Answer 3

\begin{displaymath}
le{v_{a,b}}\left({i,j} \right)=
\left\{ \begin{array}{ll}
\max({i,j})&\textrm{min({i,j})=0}\\
\min({i,j})
\left\{\begin{array}{ll}
{le{v_{a,b}}\left( {i - 1,j} \right) + 1}\\
{le{v_{a,b}}\left( {i,j-1} \right) + 1}\\
{le{v_{a,b}}\left( {i - 1,j - 1} \right) + \left[ {{a_i} \ne {b_j}} \right]}
\end{array} \right.
&\textrm{else}
\end{array} \right.
\end{displaymath}