Question

题目要求用C语言编写一个程序：输入今天的日期，输出明天的日期，请问我的设计错在哪了？

#include <stdio.h>
int main()
{
int year,month,days;
printf("Please input your data:\n");
scanf("%d,%d,%d",&year,&month,&days);
switch(month)
{
case1:
case3:
case5:
case7:
case8:
case10:
if(days<=31&&days>=0)
{
days++;
month=month;
year=year;
}
if(days=31)
{
days=1;
month++;
year=year;
}
printf("%d,%d,%d\n",year,month,days);break;
case4:
case6:
case9:
case11:
if(days<=30&&days>=0)
{
days++;
month=month;
year=year;
}
if(days=30)
{
days=1;
month++;
year=year;
}
printf("%d,%d,%d\n",year,month,days);break;

case2:
if(year%400==0||year%4==0&&year%100!=0)
{
if(days<=29&&days>=0)
{
days++;
month=month;
year=year;
}
if(days=29)
{
days=1;
month++;
year=year;
}
}
if(year%400!=0||year%4!=0)
{
if(days<=29&&days>=0)
{
days++;
month=month;
year=year;
}
if(days=29)
{
days=1;
month++;
year=year;
}
}
printf("%d,%d,%d\n",year,month,days);break;
case12:
if(days<=31&&days>=0)
{
days=days+1;
month=month;
year=year;
}
if(days=31)
{
days=1;
month=1;
year++;
}
printf("%d,%d,%d\n",year,month,days);break;
default:
printf("data error!");
}
printf("%d,%d,%d\n",year,month,days);
return 0;
}

Answer 1

case和数字之间，要有空格，你所有的case后面都没有。
其它没有明显的代码错误，不过逻辑稍微繁琐，如果是为了验证case语句，那么可以这样做。

追问

还是不行额……

追答

你代码中要求，输入格式必须用逗号分隔，必须这样输入：
2014,1,2