已知tanx=2，求2/3sin^2x+1/4cos^2x的值
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(2/3sin^2x+1/4cos^2x)
=(2/3sin^2x+1/4cos^2x)/1
=(2/3sin^2x+1/4cos^2x)/(sin^2x+cos^2x)
上下同除cos^2x得
=(2/3tan^2x+1/4)/(tan^2x+1)
=(2/3*4+1/4)/5
=7/12
=(2/3sin^2x+1/4cos^2x)/1
=(2/3sin^2x+1/4cos^2x)/(sin^2x+cos^2x)
上下同除cos^2x得
=(2/3tan^2x+1/4)/(tan^2x+1)
=(2/3*4+1/4)/5
=7/12
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