Question

因式分解的题目。怎么写 急。。

(1)25a^2-9b^2
（2）4x^2-12x+9
(3)4x^2y^2-4xy+1
(4)(x^2+1)^2-4x^2
(5)x^2-5x=0

Answer 1

(1)25a^2-9b^2
=(5a-3b)(5a+3b)

（2）4x^2-12x+9
=(2x-3)^2

(3)4x^2y^2-4xy+1
=(2xy-1)^2

(4)(x^2+1)^2-4x^2
=(x^2+1-2x)(x^2+1+2x)
=(x-1)^2(x+1)^2

(5)x^2-5x=0
x(x-5)=0
x=0或x=5

Answer 2

(1) (5a+3b)(5a-3b)
(2)(2x-3)^2
(3)(2xy-1)^2
(4)(x-1)^2 * (x+1)^2
(5) 这个是解方程吧 x = 0 或 x = 5;