Question

初三数学，化简。求过程

（2m/m＋2－m/m－2）÷m/m∧2－4

Answer 1

　　书写不规范哦！

　　解：是[2m/(m+2)-m/(m-2)]÷m/(m²-4)吧？
　　是的话，原式=[2m*(m-2)/(m+2)(m-2) -m(m+2)/(m-2)(m+2)]÷m/(m+2)(m-2)
　　=m（m-6)/(m+2)(m-2)÷m/(m+2)(m-2)
　　=m-6

Answer 2

解：
={2m(m-2)-m(m+2)}/{(m+2)(m-2)}÷m/(m²-4)
={m（m-6）}/(m²-4)÷m/(m²-4)
=m-6

Answer 3

[(2m/(m+2)-m/(m-2)]÷m/(m^2-4)
=[2m*(m-2)/(m+2)(m-2) -m(m+2)/(m-2)(m+2)]÷m/(m+2)(m-2)
=m/(m+2)(m-2)÷m/(m+2)(m-2)
=1

m^2-4可以化成(m+2)(m-2)

Answer 4

没题哦，太急了吧

追问

好了

追答

（2m/m＋2－m/m－2）÷m/m^2－4=(2m/m+2-m/m-2)x(m^2-4)/m=(2m/m+2-m/m-2)X(m+2)(m-2)/m=2(m-2)-(m+2)=m-6

Answer 5

暂无照片。怎么回事？