求sin²20+cos²80+根号三sin²20cos80的值
1个回答
2013-01-29
展开全部
sin20²+cos²80+√3sin20cos80
=(1-cos40)/2+(1+cos160)/2+√3/2(sin100-sin60)
=1-1/2cos40-1/2cos20-3/4+√3/2sin100
=1/4-1/2(cos40+cos20+√3/2sin80
=1/4-cos10cos30+√3/2sin80
=1/4-√3/2cos10+√3/2sin80
=1/4-√3/2cos10+√3/2cos10
=1/4
=(1-cos40)/2+(1+cos160)/2+√3/2(sin100-sin60)
=1-1/2cos40-1/2cos20-3/4+√3/2sin100
=1/4-1/2(cos40+cos20+√3/2sin80
=1/4-cos10cos30+√3/2sin80
=1/4-√3/2cos10+√3/2sin80
=1/4-√3/2cos10+√3/2cos10
=1/4
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询