Question

这道题谁会啊，急求答案！！！！最好有过程的

Answer 1

f(x)=√3sin ωx*cos ωx-(cos ωx)^2
=(√3/2)sin2ωx-(1/2)cos2ωx-1/2
=sin(2ωx-π/6)-1/2
T=2ω=π/2
ω=π/4
2ωx-π/6=(π/2)*x-π/6=2kπ+π/2
x=4k+4/3
2ωx-π/6=(π/2)*x-π/6=2kπ+3π/2
x=4k+10/3
x[4k+4/3,4k+10/3]减函数
2ωx-π/6=(π/2)*x-π/6=2kπ+5π/2
x=4k+16/3
x[4k+10/3,4k+16/3]增函数

2的问是什么?

Answer 2

f(x)=√3sin ωx*cos ωx-(cos ωx)^2
=(√3/2)sin2ωx-(1/2)cos2ωx-1/2
=sin(2ωx-π/6)-1/2
T=2ω=π/2
ω=π/4
2ωx-π/6=(π/2)*x-π/6=2kπ+π/2
x=4k+4/3
2ωx-π/6=(π/2)*x-π/6=2kπ+3π/2
x=4k+10/3
x[4k+4/3,4k+10/3]减函数
2ωx-π/6=(π/2)*x-π/6=2kπ+5π/2
x=4k+16/3
x[4k+10/3,4k+16/3]增函数
2的问是什么?

Answer 3

看不清楚，打出来嘛，这样才好解答