Question

求三次根号27+（根号3-1）²-（1/2）^（-1）+4/根号3+1=

Answer 1

原式=3+(3-2√3+1)-2+4(√3-1)/(3-1)
=3+4-2√3-2+2√3-2
=3.

追问

不是太明白。。

追答

哪里

Answer 2

解：v27 +(v3 -1)^2 -(1/2)^(-1) +4/(v3 +1)
=3+(3-2v3 +1) -2 +4(v3 -1)/(v3 +1)(v3-1)
=3+(4-2v3)-2 +(4v3 -4)/2
= 5-2v3 +2v3-2
=3