Question

递等式计算： 5/6×1/15÷7/18，（1/15+1/7）x15x7，10/3-2/3x9/5

递等式计算：
5/6×1/15÷7/18，（1/15+1/7）x15x7，10/3-2/3x9/5-4/5，7/9÷11/5+2/9x5/11，（1/6+7/15）÷2/5+5/12，（1/4+1/6-1/3）x1/2

Answer 1

5/6×1/15÷7/18
=1/18×18/7

=1/7
（1/15+1/7）x15x7
=1/15 x15x7+ 1/7 x15x7
=7+15
=22
10/3-2/3x9/5-4/5

=10/3-6/5-4/5
= 10/3-（6/5+4/5）
= 10/3-2
=4/3
7/9÷11/5+2/9x5/11

= 7/9×5/11 +2/9x5/11
= 5/11 ×（7/9+2/9）
=5/11
（1/6+7/15）÷2/5+5/12

= 1/6×5/2+7/15×5/2+5/12
=5/12+7/6+5/12
=5/12+5/12+7/6
=5/6+7/6
=2
（1/4+1/6-1/3）x1/2

=（3/12+2/12-4/12）x1/2
=1/12x1/2
=1/24

Answer 2

1/7
22
4/3
417/495

2

1/24
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