Question

C语言编程求s=1+12+123+12345+123456+1234567+12345678的值

C语言编程求s=1+12+123+12345+123456+1234567+12345678的值 要求使用循环实现

Answer 1

你的题目应该还要加1234吧
# include<stdio.h>
void main()
{
int i,s=1,t=1;
for(i=2;i<=8;i++)
{
t = t*10 +i; //t是这是增量
s += t; //s放和
}
printf("s=%d\n",s);
}

Answer 2

这个就是用for实现的
#include <stdio.h>
int main()
{
int num = 0;
for (int i = 1;i<=6;++i)
{
num = num*10+i;
printf("%d ",num);
}
printf("\n");
}

Answer 3

int num = 12345678;
int ret = 0;
while( num > 0 )
{
ret += num;
num /= 10;
}