计算1. xˇ2-2x+1/xˇ2/（xˇ2-1）·xˇ2+x/（x-2）（x-1）； 2.xˇ2+4x/（2-x）（x+4）-x+2/xˇ2-4
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(x²-2x+1)/x²/(x²-1)*(x²+x)/(x-2)(x-1)
=(x-1)²/[x²(x-1)(x+1)]*x(x+1)/[(x-2)(x-1)]
=1/[x(x-2)]
(x²+4x)/[(2-x)(x+4)]-(x+2)/(x²-4)
=x(x+4)/[(2-x)(x+4)]-(x+2)/[(x+2)(x-2)]
=x/(2-x)-1/(x-2)
=(x+1)/(2-x)
=(x-1)²/[x²(x-1)(x+1)]*x(x+1)/[(x-2)(x-1)]
=1/[x(x-2)]
(x²+4x)/[(2-x)(x+4)]-(x+2)/(x²-4)
=x(x+4)/[(2-x)(x+4)]-(x+2)/[(x+2)(x-2)]
=x/(2-x)-1/(x-2)
=(x+1)/(2-x)
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展开全部
(x²-2x+1)/x²/(x²-1)*(x²+x)/(x-2)(x-1)
=(x-1)²/[x²(x-1)(x+1)]*x(x+1)/[(x-2)(x-1)]
=1/[x(x-2)]
(x²+4x)/[(2-x)(x+4)]-(x+2)/(x²-4)
=x(x+4)/[(2-x)(x+4)]-(x+2)/[(x+2)(x-2)]
=x/(2-x)-1/(x-2)
=(x+1)/(2-x)
=(x-1)²/[x²(x-1)(x+1)]*x(x+1)/[(x-2)(x-1)]
=1/[x(x-2)]
(x²+4x)/[(2-x)(x+4)]-(x+2)/(x²-4)
=x(x+4)/[(2-x)(x+4)]-(x+2)/[(x+2)(x-2)]
=x/(2-x)-1/(x-2)
=(x+1)/(2-x)
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