若sin(180°+α)=-√10/10,α∈(0°,90°)
若sin(180°+α)=-√10/10,α∈(0°,90°),求[sin(-α)+(sin-90°-α)]/[cos(540°-α)+cos(-270°-α)]...
若sin(180°+α)=-√10/10,α∈(0°,90°),求[sin(-α)+(sin-90°-α)]/[cos(540°-α)+cos(-270°-α)]
展开
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询