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1个回答
展开全部
y=(x+x^1/3)^1/3
y'=1/3 (x+x^1/3)^(-2/3) (1+1/3 x^(-2/3))
y'|x=1 =1/3(1+1)^(-2/3) (4/3) =4/9 (2)^(-2/3)
y'=1/3 (x+x^1/3)^(-2/3) (1+1/3 x^(-2/3))
y'|x=1 =1/3(1+1)^(-2/3) (4/3) =4/9 (2)^(-2/3)
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