Question

求解题，谢谢。

Answer 1

(8) y=|2^x -1| = 2^x -1 ; x≥0 = -2^x +1 ; x m+1>0 and m+1≥1 m> -1 and m≥0 m≥0 case 2: x 1-m>0 and 1-m < 1 m0 => 0 -a-1/4 >0 a< -1/4 (14) f(x)= √(3-ax)/(a-1) ( a≠1) 3-ax >0 a< 3/x => a< 3 (1) ;x∈(0,1] f'(x) = -a/[2(a-1)√(3-ax)] 。