五道计算题写一下,
2个回答
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(1):4xa²-20x-24=4x(a²-5a-6)
=4x(a-6)(a+1)
(2): n²-4m²-1+4m
=n²-[(2m)²-2*1*2m+1]
= n²-(2m-1)²
= (n+2m-1)(n-2m+1)
(3):(x²+x)²-18(x²+x)+72
=(x²+x-6)(x²+x-12)
= (x+3)(x-2)(x+4)(x-3)
(4): x³+2x²y-9x-18y
=x(x²-9)+2y(x²-9)
=(x²-9)(x+2y)
= (x+3)(x-3)(x+2y)
(5):3x/(x-5)-4=7/(5-x)
(3x+7)/(x-5)=4
3x+7=4x-20
x=27
=4x(a-6)(a+1)
(2): n²-4m²-1+4m
=n²-[(2m)²-2*1*2m+1]
= n²-(2m-1)²
= (n+2m-1)(n-2m+1)
(3):(x²+x)²-18(x²+x)+72
=(x²+x-6)(x²+x-12)
= (x+3)(x-2)(x+4)(x-3)
(4): x³+2x²y-9x-18y
=x(x²-9)+2y(x²-9)
=(x²-9)(x+2y)
= (x+3)(x-3)(x+2y)
(5):3x/(x-5)-4=7/(5-x)
(3x+7)/(x-5)=4
3x+7=4x-20
x=27
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